**Eight cubes are glued together to form the figure shown. The length of an edge of each cube is 3 cm. The entire figure is covered in paint. How many square centimeters are covered in paint?**

METHOD 1: Strategy: Temporarily disregard the first 1/5 mile.Dan pays $2.00 for the first fifth mile and $7.60 for the rest of the ride. Each fifth of a mile costs 40¢, and 760 ÷ 40 = 19. The $7.60 pays for a ride of 19 fifths of a mile. Adding 1/5 mile for the first $2.00, the longest ride Dan can afford is 20/5 or 4 miles.METHOD 2: Strategy: Make a table.The cost increases by $.40 for each fifth of a mile. When the desired amount is reached, the taxi will have traveled a length of 20/5 or 4 miles. METHOD 3: Strategy: Use algebra.Let N = the number of fifths of a mile after the first fifth mile that Dan can ride. 2.00 + .40N = 9.60 .40N = 7.60 (Subtract 2.00 from each side) N = 19 (Divide each side by .40) Add the first fifth of a mile, bringing the length of the ride to 20/5 or 4 miles. |
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March 2012
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